AljabaR matriKz... &$%*!@#

So.. it's by reQuesT,, coz we have a Math assignmenT,, and Kartini ask me to share the way to do the homework, but only the first number.. okay..

So we have Aljabar Matriks here... (alah.. =D)

soale sperti di bawah ini

=

Dan, tugas Qta,, seperti terlihat,, yeah,, of course.. find the value of a, b, c and d.

so here we go..

#Jadi Diketahui :
a - b = 8
3d + c = 7
b + c = 1
2a - 4d = 6

# So.. -->
a - b = 8 -> b = a - 8
b + c = 1 -> b = 1 - c

Jadi dari sini bisa dieliminasi
--> a - 8 = 1 - c
--> a + c = 9
--> c = 9 - a

# nexT..
--> 3d + c = 7 --> (Nilai c kita ganti dari persamaan sebelumnya)
--> 3d + 9 - a = 7
--> 3d - a = -2

# 3d - a = -2
-4d + 2a = 6 (2 persamaan ini di eliminasi)
--> 6d - 2a = -4
-4d + 2a = 6
--> 2d = 2
d = 1

# 3d + c = 7
3 + c = 7
c = 4

# b + c = 1
b + 4 = 1
b = -3

# a - b = 8
a - (-3) = 8
a + 3 = 8
a = 5

So,, we've got the answer..

nilai a = 5, b = -3, c = 4, d =1.

ok,, no 1 ini aja ye... coz ,, susah nulisinnya.. T.T

hee,,, peace.. =)